I would like to find the power loss over 0.3 seconds due to a resistance of 0.0015 ohms with a current following the function: I = e-15.24t-e-39984.75t where t is time. I would have imagined summing all the current over that 0.3 second period via integration would then allow me to find the power lost in that 0.3 second time period using this sum in place of the current (I) in the usual power formula P=I2R. my problem is I think the integral of current is charge? and then the working I have just shown wouldn't make sense I don't think? Any help would be appreciated.