Decomposing Wave Patterns: ψ(x)=sin4x

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Wave patterns can be decomposed into simpler components, as illustrated by the function ψ(x) = sin4x, which can be expressed using double angle formulas. The decomposition shows that ψ(x) can be represented as a sum of cosine terms, specifically with coefficients for even values of n, such as c0 and c2. The discussion raises a question about why only even coefficients appear for these specific wave functions, while odd coefficients may arise in other functions. The participants explore the implications of this pattern and confirm that it is consistent across similar wave functions. Understanding this decomposition is essential for analyzing complex wave patterns effectively.
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Homework Statement


I read from a book (obtained from a library) which stated that:

"Wave patterns, no matter how complicated, can always be written as a sum of simple wave patterns.
Ex: ψ(x) = sin2x = 1/2 + cos2x/2
"

I understand that ψ(x) has been decomposed with double angle trignometry formulas.

"More generally, it is possible to decompose the wave function into components corresponding to a constant pattern plus all possible wavelengths of hte form 2pi/n with n, an integer. That is, we can find coefficients cn such that:

ψ(x) = sigma (n=0 to infinite) cn cosnx In this ex, c0 = 1/2 and c2 = -1/2. All other coefficents are zero.
"

So...since the statement said, "wave patterns, no matter how complicated," I decided to try out with ψ(x) = sin4x out of curiosity...

Homework Equations

The Attempt at a Solution


ψ(x) = sin4x
I used double angle formulas to get:
ψ(x) = (1-cos2x)2/4...meaning the wave pattern is decomposed into:
ψ(x) = 1/4 + cos2x/2 + cos22x/4

However, I am trying to figure out about

"ψ(x) = sigma (n=0 to infinite) cn cosnx In this ex, c0 = 1/2 and c2 = -1/2. All other coefficents are zero.
" Could someone explain how to use this method so that I can try it out on ψ(x) I just made up?
 
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cos22x = 1 - sin22x
and use the example.
 
ψ(x) = 1/4 + cos2x/2 + cos22x/4
= 1/4 + cos2x/2 + 1/4 - sin22x/4
= 1/2 - cos2x/x -1/4(1/2)(1-cos2x)
= 3/8 - 3cos2x/8...since it is now in two terms...I guess c0 = 3/8 and c2 = -3/8?
 
yes.
 
Hmm..but, I don't understand why only even values of n show up? I mean, why is c1 or c3 = 0, not not for n = 0 and 2? It seems it happens to both ψ(x) = sin2x and sin4x? Or, am I thinking too much?
 
terp.asessed said:
ψ(x) = 1/4 + cos2x/2 + cos22x/4
= 1/4 + cos2x/2 + 1/4 - sin22x/4
= 1/2 - cos2x/x -1/4(1/2)(1-cos2x)
= 3/8 - 3cos2x/8...since it is now in two terms...I guess c0 = 3/8 and c2 = -3/8?
On line 3, cos4x will appear.

terp.asessed said:
Hmm..but, I don't understand why only even values of n show up? I mean, why is c1 or c3 = 0, not not for n = 0 and 2? It seems it happens to both ψ(x) = sin2x and sin4x? Or, am I thinking too much?

Odd values of n will show up for some other functions.
 
td21 said:
yes.
No. Sorry for that.
 
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