How Is Oxygen Partial Pressure Maintained in Deep Sea Diving?

  • Thread starter Thread starter clipperdude21
  • Start date Start date
  • Tags Tags
    Pressure
AI Thread Summary
At a depth of 50 meters, the total pressure experienced by the diver is approximately 605,700 Pa, leading to an oxygen partial pressure of about 127,197 Pa, calculated using the formula P=patm + pgh. To maintain the same oxygen partial pressure as at the surface, a mixture of helium and air is required. Using Dalton's Law, the appropriate mixing ratio can be determined by ensuring that the oxygen partial pressure from the mixture equals 127,197 Pa. The calculations involve adjusting the helium and air proportions to achieve this balance. Understanding these principles is crucial for safe deep-sea diving practices.
clipperdude21
Messages
48
Reaction score
0
1. A deep sea diver has descended a distance of 50m below the ocean surface. Asummer that he is supplied with air from the survace.
a) what is oxygen partial pressure in the lungs of the diver at this depth.
b) suppose we want the oxygen partial pressure in the lungs of the diver at this depth to be the same as that at the surface. This can be done by providing the diver with a mixutre of helium and air. Use Dalton;s Law to compute the proper mixing ratio in moles between helium and air and explain the mechanism.




Homework Equations





3. (a) I got this right I am pretty sure. I just did P=patm + pgh and got 605,700. Then multiplied it by 0.21 since oxygen is 21% of air and got 127,197 Pa.
(b) I couldn't do this one!
 
Physics news on Phys.org
It would be helpful if one showed the steps and units.

for part b. at the surface the pressure of air is 1 atm, 14.7 psia, or 101325 Pa, of which ~0.21 is oxygen.

What is the mixture of He/O2 such that the oxygen partial pressure is the same as the surface pressure when the diver is 50 m below the surface?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top