Definition of first law of thermodynamic?

AI Thread Summary
The first law of thermodynamics states that the change in internal energy of a closed system is equal to the heat added to the system and the work done on it, expressed as ΔU = ΔQ + ΔW. Both definitions (a) and (b) can be interpreted correctly, but clarity in terms is crucial; definition (a) emphasizes the change, while definition (b) focuses on the increase. The distinction between work done on versus by the system is important, as it affects the sign of the terms involved. Additionally, the first law applies to both closed and open systems, as long as all energy changes are accounted for. Understanding these nuances is essential for accurate application in thermodynamic problems.
mugen715
Messages
9
Reaction score
0

Homework Statement



What is the definition for first law of thermodynamic? I was confused and which one is correct?

(a) The CHANGE in internal energy of a closed system is equal to the heat that enters a system and the workdone on the system

OR

(b) The INCREASE in internal energy of a closed system is equal to the heat that enters a system and the workdone on the system

Homework Equations



ΔU = ΔQ + ΔW

The Attempt at a Solution



In the exam, I use definition (a), but my teacher marked it wrong. But when i referred to all my textbooks, both definition can be used. So could anyone out there figure out which is correct?
 
Physics news on Phys.org
mugen715 said:

Homework Statement



What is the definition for first law of thermodynamic? I was confused and which one is correct?

(a) The CHANGE in internal energy of a closed system is equal to the heat that enters a system and the workdone on the system

OR

(b) The INCREASE in internal energy of a closed system is equal to the heat that enters a system and the workdone on the system

Homework Equations



ΔU = ΔQ + ΔW

The Attempt at a Solution



In the exam, I use definition (a), but my teacher marked it wrong. But when i referred to all my textbooks, both definition can be used. So could anyone out there figure out which is correct?
The common convention is: Q = ΔU + W. This means the heat flow into a system is equal to the change in internal energy of the system + the Work done BY the system.

If one uses Q = ΔU - W, the W is the work done ON the system.

Since Q and W are not state variables, there can be no change in Q or W.

P.S. The reason for your mark may be that you did not make it clear that heat flow into the system and work done BY the system can be negative. If you made that clear (and if you were using b. and stated that the increase in U can be negative) it would be correct.

Re: closed system: so long as you account for all the internal energy changes, heat flow and work done, the system does not have to be closed. A steam engine is a closed system but an internal combustion engine is an open system. The first law applies to both.

AM
 
Last edited:
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top