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Definition of 'with the vertical' in this question?

  1. Mar 20, 2017 #1

    ehf

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    1. The problem statement, all variables and given/known data
    J5VjCPu.jpg
    (please ignore something that is not english)
    2. Relevant equations
    ac=v^2/r
    Fc is about 6.0E3 N and ac is about 5.0 m/s^2
    (b) is the problem...
    3. The attempt at a solution
    what is 'with the vertical' here? the direction/opposite of ac or the direction of v?
     
  2. jcsd
  3. Mar 20, 2017 #2
    It means the angle with the vertical. So a strictly vertical force downward would be 0 degrees. A strictly horizontal (sliding) force would be 90 degrees.
     
  4. Mar 20, 2017 #3

    ehf

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    sliding=horizontal=velocity direction and vertical=ac direction then?
     
  5. Mar 20, 2017 #4
    The force applied to the car by the pavement will consist of 2 components:
    - 1) There will be a vertical component that supports the mass of the car against gravity.
    - 2) There will be a horizontal centripetal force that holds the car along its circular path.

    The angle of the total force against the car with vertical will be an arc tangent of the ratio of these forces.
     
  6. Mar 21, 2017 #5

    ehf

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    Oh thank you now I understand the meaning
     
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