Density Change Caused by Temp. Change

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The discussion centers on the relationship between temperature change and density change, specifically that the change in density (Δρ) is given by Δρ = -βρΔT. Participants clarify the algebra involved in deriving this equation, highlighting the importance of correctly identifying the initial and final densities (ρ1 and ρ2). A participant initially misinterprets the variables but later acknowledges the error after reviewing the calculations. The conversation emphasizes the need for precision in understanding how volume changes with temperature affects density. The resolution suggests that the original problem statement may contain a typographical error.
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[SOLVED] Density Change Caused by Temp. Change

Homework Statement


Show that the change in the density \rho of a substance, when the temperature changes by \Delta T, is given by \Delta \rho = - \beta \rho \Delta T.

Homework Equations


\rho = \frac{m}{V}
\Delta V = \beta V \Delta T

The Attempt at a Solution


Let \rho_1 and \rho_2 be the densities of the substance before and after the temp. change \Delta T. After some algebra, I get:

\Delta \rho = \rho_2 - \rho_1 = - \beta \rho_2 \Delta T

This differs from that given in the problem statements because \rho is \rho_1 in the above. I guess this must be typo right?
 
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What are the explicit densities before and after the increase in temperature? That is the key to getting this and a lot of people make a mistake. The density before is simple:

\rho_0=\frac{m}{V_0}

but the final density is:

\rho = \frac{m}{(V_0+\Delta V)}
 
Are you implying that I made a mistake? I have checked the algebra twice and I still get the result I got. If I use what you wrote for the densities, I still get the same result.
 
Ahh ok I see what you've done, my mistake. Yes I get the same answer as you so I'd wager it was a spelling error unless we both made the same mistake.
 
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