Derivation of angle of deviation in a prism

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derivation of an expression for the angle of deviation in a prism, in terms of [tex]\theta[/tex]a and [tex]\theta[/tex]g and A


Homework Equations


([tex]\theta[/tex]a - [tex]\theta[/tex]g ) + ([tex]\theta[/tex]a' - [tex]\theta[/tex]g' ) = D

A = [tex]\theta[/tex]g + [tex]\theta[/tex]g'

i get stuck trying to put [tex]\theta[/tex]a' into the terms the question states, anyone have an idea? thanks,
 
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You can work out the refractive index from [itex]\theta_a[/itex] and [itex]\theta_g[/itex].
 
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