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Derivation of angle of deviation in a prism

  1. May 13, 2010 #1

    derivation of an expression for the angle of deviation in a prism, in terms of [tex]\theta[/tex]a and [tex]\theta[/tex]g and A

    2. Relevant equations
    ([tex]\theta[/tex]a - [tex]\theta[/tex]g ) + ([tex]\theta[/tex]a' - [tex]\theta[/tex]g' ) = D

    A = [tex]\theta[/tex]g + [tex]\theta[/tex]g'

    i get stuck trying to put [tex]\theta[/tex]a' into the terms the question states, anyone have an idea? thanks,
  2. jcsd
  3. May 16, 2010 #2
    You can work out the refractive index from [itex]\theta_a[/itex] and [itex]\theta_g[/itex].
    Last edited: May 16, 2010
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