Riles246
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Homework Statement
d/dT (e-E0/(kT))
Homework Equations
d/dx(ex) = ex
The Attempt at a Solution
e-E0/(kT) * E0/kT2 ?
Do you use the chain rule on the exponent of e?
Looks spot on to meRiles246 said:Homework Statement
d/dT (e-E0/(kT))
Homework Equations
d/dx(ex) = ex
The Attempt at a Solution
e-E0/(kT) * E0/kT2 ?
Do you use the chain rule on the exponent of e?