Derivative of exponential functions

Riles246
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Homework Statement



d/dT (e-E0/(kT))

Homework Equations



d/dx(ex) = ex

The Attempt at a Solution



e-E0/(kT) * E0/kT2 ?

Do you use the chain rule on the exponent of e?
 
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Riles246 said:

Homework Statement



d/dT (e-E0/(kT))

Homework Equations



d/dx(ex) = ex

The Attempt at a Solution



e-E0/(kT) * E0/kT2 ?

Do you use the chain rule on the exponent of e?
Looks spot on to me :approve:. And yes, you would use the chain rule (followed by the power rule on the exponent) to differentiate the function.
 
if u=u(x),
d/dx (e^u) = e^u du/dx
d/dx (e^(1/x)) = e^(1/x) (-1)/(x^2)
d/dx (e^(a/x)) = e^(a/x) (-a)/(x^2)
d/dx (e^(a/bx)) = e^(a/bx) (-a/b)/(x^2)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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