I'm working through Kline's Calculus book, and am at the chapter on Integration on Differentiation of Trig Functions. A question asks to find the derivative of:(adsbygoogle = window.adsbygoogle || []).push({});

(I've labeled all equations for easy reference)

(1) y = sin x * cos x

unlike the solution guide which advocates using the product rule, I decided to use the product to sum trig identity and work from there. Unfortunately it looks like my answer is incorrect, and I'd like to know why.

So, using the trig identity:

(2) sin a * cos b = (sin(a+b) + sin(a-b)) / 2

I computed:

(3) y = (sin(x + x) + sin(x - x)) / 2

then,

(4) y = (sin(2x) + sin(0)) / 2

which simplifies to:

(5) y = (sin(2x)) / 2

Then By the chain rule:

(6) y' = (2 * cos(2x)) / 2

which yields:

(7) y' = cos(2x)

yet the solution guide has

(8) y' = -sin^2(x) + cos^2(x) which is clearly different.

Where did I go wrong?

**Physics Forums - The Fusion of Science and Community**

# Derivative of y = sin x * cos x

Have something to add?

- Similar discussions for: Derivative of y = sin x * cos x

Loading...

**Physics Forums - The Fusion of Science and Community**