- #1
philadelphia
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1. Find y' if xey + 1 = xy
The attempt at a solution
I separated the y:
y= ey + 1/x
After deriviation:
y' = e2(dy/dx) -1/(x2)
Is this correct? If so, how do solve after since this question is m/c which one of choices is (y-ey)/ (xey-1), though it could be none of above.
2. Find the definite integral that represents the area of the surface formed by revolving the graph of f(x) = x2 on the interval [0, sqrt(2)] about the x axis
This is another m/c problem
The attempt at a solution
The problems asks for the proper shell method formula I beleive.
one of the choice is 2pi [tex]\int[/tex] [tex]^{sqrt(2)}_{0}[/tex] x2[tex]\sqrt{1+x}[/tex]4dx
and another 2pi [tex]\int[/tex] [tex]^{2}_{0}[/tex] y[tex]\sqrt{1+1/y}[/tex]dy
ok my question is where do they get a sqrt for part of the answer
3. Find the volume of the solid formed by revolving the region bounded by y=2x2 + 4x and y = 0 about the y-axis.
Since the volume is forming on the y-axis, how do I separate x from the given function
The attempt at a solution
I separated the y:
y= ey + 1/x
After deriviation:
y' = e2(dy/dx) -1/(x2)
Is this correct? If so, how do solve after since this question is m/c which one of choices is (y-ey)/ (xey-1), though it could be none of above.
2. Find the definite integral that represents the area of the surface formed by revolving the graph of f(x) = x2 on the interval [0, sqrt(2)] about the x axis
This is another m/c problem
The attempt at a solution
The problems asks for the proper shell method formula I beleive.
one of the choice is 2pi [tex]\int[/tex] [tex]^{sqrt(2)}_{0}[/tex] x2[tex]\sqrt{1+x}[/tex]4dx
and another 2pi [tex]\int[/tex] [tex]^{2}_{0}[/tex] y[tex]\sqrt{1+1/y}[/tex]dy
ok my question is where do they get a sqrt for part of the answer
3. Find the volume of the solid formed by revolving the region bounded by y=2x2 + 4x and y = 0 about the y-axis.
Since the volume is forming on the y-axis, how do I separate x from the given function
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