Deriving Equations for Particle Motion and Momentum Conservation

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Homework Statement



[PLAIN]http://img51.imageshack.us/img51/4562/mecj.jpg

Homework Equations





The Attempt at a Solution



How do I go about showing LHS = RHS in each of these? (\wedge denotes cross product)

What is \dot{r}=\dot{x_1}-\dot{x_2} and \dot{R} ?
 
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I would interpret the dot over the variable as being the derivative with respect to time (that's more a physics notation than mathematics). Thus \dot{r}=\dot{x_1}-\dot{x_2} is the rate at which the distance between the two objects is changing and \dot{R} is the speed at which their center of mass is moving.
 
HallsofIvy said:
I would interpret the dot over the variable as being the derivative with respect to time (that's more a physics notation than mathematics). Thus \dot{r}=\dot{x_1}-\dot{x_2} is the rate at which the distance between the two objects is changing and \dot{R} is the speed at which their center of mass is moving.

So how do I find them?

ie. how do I differentiate R and r?
 
Am I right in saying the LHS of (i) is

\displaystyle\frac{1}{2} (m_1 +m_2) \left| \frac{m_1\underline{\dot{x_1}}+m_2\underline{\dot{x_2}}}{m_1 + m_2} \right| ^2 + \frac{1}{2} \frac{m_1 m_2}{m_1 + m_2} \left| \underline{\dot{x_1}} - \underline{\dot{x_2}} \right| ^2 ?

If so, where do I go now?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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