Deriving the 4th equation of motion

AI Thread Summary
The discussion focuses on deriving the fourth equation of motion, v² = v₀² + 2aD, using the second and third equations of motion. The user initially seeks assistance in substituting time from the second equation into the third to eliminate time from the derivation. They express confusion over the distribution of terms and the resulting form of the equation. Ultimately, the user resolves their issue independently. The thread highlights the process of deriving motion equations and the common challenges faced in physics calculations.
danksnaks
Messages
2
Reaction score
0
1. All I need to do is derive the 4th equation of motion being v2= v02+2aD from the second (t=(v-v0)/a) and third (D=1/2at2+v0t).
2. In this case D= (Ending-initial distance) V0= Initial Veolocity
3. By having the second equation solved for t I could substitute it in an completely eliminate time and I end up with D=1/2a((v-v0)/a))2+v0((v-v0)/a). Past this point I knwo to distribute the terms, but I have no idea what the correct forms look like because I always ended up with a slight different in the term hooked to 1/2a. Any help here?
 
Physics news on Phys.org
I lied. I figured it out.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top