Deriving the formula for arctanh(x)

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Homework Statement



"starting from the definition of tanhx in terms of exponentials, prove that...

arctanh(x)=1/2log((1+x)/(1-x))

This is such a simple equation but I'm having a hard time proving it, can anyone help?

Cheers


Homework Equations





The Attempt at a Solution

 
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If y= tanh(x) then
[tex]y= \frac{e^x- e^{-x}}{e^x+ e^{-x}}[/tex]
Now use the standard method of finding an inverse function: solve that equation for x.