Deriving the Fourth Mass in a Hanging Masses Problem

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The discussion revolves around deriving the fourth mass (m4) in a system of four hanging masses connected by ropes. The key equation presented is m4 = (m1T2/T1 - T2) - m2 - m3, derived using the relationships between tension and mass. Participants confirm that the solution is valid, although alternative expressions for m4 can also be formulated. There is a suggestion to clarify the arrangement with a diagram for better understanding. Overall, the calculations and reasoning provided are deemed correct, addressing the original homework question effectively.
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Homework Statement



There are four masses hanging by a rope from the
ceiling in the simplest arrangement possible, mass 4 is attached by the rope to mass three right above it,
mass three is attached by a rope to mass 2 right above it, mass 2 is attached by the rope to mass 1 right above it
and mass one is attached by the rope to the ceiling. So the masses are hanging vertically from the ceiling attached by the rope.
Two of the tensions and three of the masses have been measured.
We know: T1 T2 m1 m2 m3 Show that the fourth mass can be expressed as

m4 = (m1T2/T1 - T2) - m2 - m3

Homework Equations



F = mg

The Attempt at a Solution



We know that m4g + m3g + m2g = T2
so m4 = (T2/g) - m2 - m3 since multiplying the first term by m1/m1 is the same as multiplying the term by one, we get m4 = (m1T2/m1g) - m2 - m3 using the fact that T1 - T2 = m1g and substituting this equation in the denominator we get m4 = (m1T2/T1 - T2) - m2 - m3 QED

Is this right? Did I answer the question properly? Just seems like I cheated. If you can point me in the direction of a better answer I'd greatly appreciate it.
 
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Stochastic13 said:
There are four masses hanging by a rope from the
ceiling.
Please describe the arrangement in more detail. A diagram would help.
 
It's the simplest arrangement possible, mass 4 is attached by the rope to mass three right above it, mass three is attached by a rope to mass 2 right above it, mass 2 is attached by the rope to mass 1 right above it and mass one is attached by the rope to the ceiling. So the masses are hanging vertically from the ceiling attached by the rope. I also forgot to mention that I used the fact that T1 - T2 = m1g in the attempted solution portion of my post, then I used this equation in the last part of my answer to arrive at the final conclusion.
 
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Stochastic13 said:
Show that the fourth mass can be expressed as

m4 = (m1T2/T1 - T2) - m2 - m3
I assume you missed a parentheses and meant to write:
m4 = m1T2/(T1 - T2) - m2 - m3

But your work looks fine to me.

Of course there are many ways to express m4; this is just one of them. For example, since you know T2, you should be able to express m4 in terms of T2, m2, and m3.
 
Thanks, it just seemed way to simple, so I wasn't sure if I did it right.
 
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