Deriving the Rotation Matrix of a Beam Element

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Homework Help Overview

The discussion revolves around deriving the rotation matrix for a beam element that is rotated around the x, y, and z axes. Participants are examining the mathematical representation of these rotations and their implications.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are analyzing the components of the rotation matrix, questioning the placement of minus signs in the matrices for rotations about the axes. There are attempts to verify the correctness of the matrices provided and to understand the derivation process.

Discussion Status

The discussion is active, with participants providing different perspectives on the placement of signs in the rotation matrices. Some participants are exploring the implications of the right-hand rule on the direction of rotations, while others are attempting to reconcile discrepancies between their results and established references.

Contextual Notes

There are references to external sources, such as a Wikipedia page, which may indicate differing conventions or interpretations regarding rotation matrices. Participants are also considering the implications of positive angles in relation to the right-hand rule.

dirk_mec1
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Homework Statement



The rotation matrix below describes a beam element which is rotated around three axes x,y and z. Derive the rotation matrix.

http://img194.imageshack.us/img194/3351/60039512.png

http://img808.imageshack.us/img808/159/64794596.png

Homework Equations


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The Attempt at a Solution


I can see where the x-values (CXx CYx CZx) come from. They're just the projections of the rotated x-axes (the one with rotation alpha and beta). But I don't understand how the rest is derived can somebody help me?
 
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Rotation about the x-axis through angle [itex]\alpha[/itex] is given by the matrix
[tex]\begin{bmatrix}1 & 0 & 0 \\ 0 & cos(\alpha) & -sin(\alpha) \\ 0 & sin(\alpha) & cos(\alpha)\end{bmatrix}[/tex]

Rotation about the y-axis through angle [itex]\beta[/itex] is given by the matrix
[tex]\begin{bmatrix}cos(\beta) & 0 & -sin(\beta) \\ 0 & 1 & 0 \\ sin(\beta) & 0 & cos(\beta)\end{bmatrix}[/tex]

Rotation about the z-axis through angle [itex]\gamma[/itex] is given by the matrix
[tex]\begin{bmatrix} cos(\gamma) & -sin(\gamma) & 0 \\ sin(\gamma) & cos(\gamma) & 0 \\ 0 & 0 & 1\end{bmatrix}[/tex]

The result of all those rotations is the product of those matrices. Be sure to multiply in the correct order.
 
I suspect that there's a minus sign somewhere wrongly placed in your matrices Halls, am I correct? I moved the minus sign in your second matrix to the lower sine but there's still something wrong for this is my result:

Code:
[                        cos(a)cos(b),               -sin(b),                           cos(b)sin(a)                ]
[ sin(a)sin(c) + cos(a)cos(c)sin(b)         cos(b)cos(c)         cos(c)*sin(a)sin(b) - cos(a)sin(c) ]
[ cos(a)sin(b)sin(c) - cos(c)sin(a)        cos(b)*sin(c)     cos(a)cos(c) + sin(a)sin(b)sin(c)       ]
 
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No, all of the minus signs are correctly placed. I am, of course, assuming that a positive angle gives a rotation "counterclockwise" looking at the plane from "above"- from the positive axis of rotation.
 
dirk_mec1 said:

Homework Statement



The rotation matrix below describes a beam element which is rotated around three axes x,y and z. Derive the rotation matrix.

http://img194.imageshack.us/img194/3351/60039512.png

Look at your diagram. Are all of those rotations positive by the right hand thumb rule? (Hint: The answer is no.)
 
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