Deriving Thrust from Newton II for Rocket Motors

AI Thread Summary
The discussion focuses on deriving the thrust produced by a rocket motor using Newton's second law. The thrust is defined as the force generated by the ejection of material at a constant velocity and mass ejection rate. Participants explore the relationship between force, momentum change, and mass flow rate, emphasizing the application of Newton's laws. One participant attempts to derive the thrust formula but expresses uncertainty about their approach. The conversation highlights the need for a clear understanding of momentum conservation in the context of rocket propulsion.
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Homework Statement



Derive from Newton II the thrust (the force produced by the rocket exhaust) achieved by a rocket motor which ejects material with constant velocity u and mass ejection rate a.


Homework Equations





The Attempt at a Solution



Not sure...I know how to derive vf = vi + u ln(mi/mf) but that's not what its asking for..

So my attempt

F = mdv/dt

then using what we have for m i come to

F = a(vf-vi)/ln(M/m-at)

is this right?
 
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bon said:

Homework Statement



Derive from Newton II the thrust (the force produced by the rocket exhaust) achieved by a rocket motor which ejects material with constant velocity u and mass ejection rate a.

Homework Equations


The Attempt at a Solution



Not sure...I know how to derive vf = vi + u ln(mi/mf) but that's not what its asking for..

So my attempt

F = mdv/dt

then using what we have for m i come to

F = a(vf-vi)/ln(M/m-at)

is this right?
Newton's second and third laws of motion apply. Rather than F = ma, write the second law as:

\vec{F} = \frac{d\vec{p}}{dt}

The third law for an object on which no external forces act can be written:

\sum \vec{F_i} = \sum {\frac{d\vec{p_i}}{dt} = 0

which in this case reduces to:

\frac{d\vec{p_{rocket}}}{dt} = - \frac{d\vec{p_{gas}}}{dt}

For the gases fired out the end of the rocket, the velocity relative to the rocket is constant. What gives it a non-zero time rate of change of momentum?

AM
 
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