Derivitive with ln - don't understand

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Homework Statement



Differentiate the following:
y = ln(2x^2 - 2) / x^2 - 1



The Attempt at a Solution



The answer is y' = -ln(2x^2 - 2)(2x)(x^2 - 1)^-2 + 4x / 2x^2 - 2 (x^2 - 1)^-1

I understand all of it except 4x / 2x^2 - 2, how does ln(2x^2 - 2) derive into 4x / 2x^2 - 2?
 
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\frac{d}{dx}(ln(f(x))=\frac{f'(x)}{f(x)}
 
Oh okay, thanks, never seen that one before.
 
zeion said:
Oh okay, thanks, never seen that one before.
If you look closely, you'll notice that's just the chain rule...
 
Really? How?
 
To see how it is the chain rule, think about what the derivative of ln x is.
 
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