Describe the electron's subsequent circular motion

Thread starter jan2905
Start date Jan 23, 2009
Tags

Circular Circular motion Motion

AI Thread Summary

An electron projected upward into a uniform magnetic field directed into the page will experience circular motion due to the Lorentz force acting on it. The direction of the electron's motion is clockwise, as determined by the Right-Hand Rule, despite the electron having a negative charge. The radius of the circular path can be calculated using the formula r = mv/(eB), where m is the mass of the electron, v is its speed, e is the charge of the electron, and B is the magnetic field strength. This analysis confirms the electron's behavior in the magnetic field. Understanding these principles is essential for studying charged particle dynamics in magnetic fields.

Jan 23, 2009

jan2905

An electron (mass=m, charge=-e) is projected with speed v upward, in the plane of the page, into a region containing a uniform magnetic field B, that is directed into the plane of the page. Describe the electron's subsequent circular motion.

I tried using the Right-Hand Rule.

I said: Clockwise rotation; radius of path = mv/(eB). Is this correct?

Physics news on Phys.org

Jan 23, 2009

Dadface

Yes.

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »

Thread 'Struggle to understand the concept of the question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

View full post »