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I was thinking of something simpler, though it may be equivalent: the sine rule.Jeroen Staps said:I now have the following equation that seems to be correct:
φ = cos-1((AC-CD*cos(γ-θ)) / √(AC2+CD2-2*AC*CD*cos(γ-θ))) + 90 - α
I was thinking of something simpler, though it may be equivalent: the sine rule.Jeroen Staps said:I now have the following equation that seems to be correct:
φ = cos-1((AC-CD*cos(γ-θ)) / √(AC2+CD2-2*AC*CD*cos(γ-θ))) + 90 - α
As I posted, you can use angles θ and φ to write a force balance equation.Jeroen Staps said:But how do I use this to describe the location of D when there is a certain mass hanging at D and there is a certain pulling force in AD?
I used the cosine rule twice to come up with thisharuspex said:I was thinking of something simpler, though it may be equivalent: the sine rule.
So does my post #45 make sense?haruspex said:As I posted, you can use angles θ and φ to write a force balance equation.
I believe it is a statics question, how the equilibrium position depends on the applied tension.BvU said:Adding constant acceleration should be easy.
The question is: What is the position of the pulley when there is a given mass of the load and a given ratio between the force of gravity and the pulling force.haruspex said:I believe it is a statics question, how the equilibrium position depends on the applied tension.
Which is the same as I wrote.Jeroen Staps said:The question is: What is the position of the pulley when there is a given mass of the load and a given ratio between the force of gravity and the pulling force.