Describe the position of a pulley attached to a sling

In summary, the floating pulley changes its position depending on the force applied to the cable at the drum.
  • #36
haruspex said:
I meant to write
OK, I see
 
Physics news on Phys.org
  • #37
haruspex said:
I meant to write
But then there are still two unknowns, namely θ and φ.
 
  • #38
Jeroen Staps said:
But then there are still two unknowns, namely θ and φ.
Doesn’t matter. At this stage we are just trying to find a relationship between them. Next step will be to involve them in force balance equations.
In fact, if you are stuck on getting that relationship, set that aside and move onto the other equations.
 
  • #39
haruspex said:
Doesn’t matter. At this stage we are just trying to find a relationship between them. Next step will be to involve them in force balance equations.
In fact, if you are stuck on getting that relationship, set that aside and move onto the other equations.
Alright I'll try to find the relationship then.
 
  • #40
Still stuck on finding the relationships :(
 
  • #41
Now I have that: AD2=AC2+CD2-2*AC*CD*cos(γ-θ), with γ the angle ∠ACB. But still don't understand the force balance equations
 
  • #42
Been a while. Remind us what force balance equations you have gathered so far and which one you don't understand :wink:
 
  • #43
BvU said:
Been a while. Remind us what force balance equations you have gathered so far and which one you don't understand :wink:
Was on holiday ;) , I just don't understand how I can solve this problem when there are more than one unknowns
 
  • #44
Jeroen Staps said:
Still stuck on finding the relationships :(
First, find all the angles of triangle ACD in terms of α, θ, φ.
 
  • #45
BvU said:
Been a while. Remind us what force balance equations you have gathered so far and which one you don't understand :wink:
upload_2019-3-7_13-26-17.jpeg

Does this make sense?
 

Attachments

  • upload_2019-3-7_13-26-17.jpeg
    upload_2019-3-7_13-26-17.jpeg
    29.7 KB · Views: 286
  • #46
haruspex said:
First, find all the angles of triangle ACD in terms of α, θ, φ.
upload_2019-3-7_13-26-54.jpeg


Need more?
 

Attachments

  • upload_2019-3-7_13-26-54.jpeg
    upload_2019-3-7_13-26-54.jpeg
    30.5 KB · Views: 595
  • #47
Jeroen Staps said:
Now I have that: AD2=AC2+CD2-2*AC*CD*cos(γ-θ), with γ the angle ∠ACB. But still don't understand the force balance equations
And I have that: BD2=AB2+AD2-2*AB*AD*cos(α2) when you substitute AD from the earlier post in this equation then you have an equation to solve α2 with θ as unknown and α2 is equal to α-(180-90-φ). So I can express θ in φ
 
Last edited:
  • #48
Jeroen Staps said:
That’s good. You know the lengths of two sides of ACD. What equation can write connecting those with two of its angles?
 
  • #49
haruspex said:
That’s good. You know the lengths of two sides of ACD. What equation can write connecting those with two of its angles?
I now have the following equation that seems to be correct:

φ = cos-1((AC-CD*cos(γ-θ)) / √(AC2+CD2-2*AC*CD*cos(γ-θ))) + 90 - α
 
Last edited:
  • #50
Jeroen Staps said:
I now have the following equation that seems to be correct:

φ = cos-1((AC-CD*cos(γ-θ)) / √(AC2+CD2-2*AC*CD*cos(γ-θ))) + 90 - α

But how do I use this to describe the location of D when there is a certain mass hanging at D and there is a certain pulling force in AD?
 
  • #51
Jeroen Staps said:
I now have the following equation that seems to be correct:

φ = cos-1((AC-CD*cos(γ-θ)) / √(AC2+CD2-2*AC*CD*cos(γ-θ))) + 90 - α
I was thinking of something simpler, though it may be equivalent: the sine rule.
 
  • #52
Jeroen Staps said:
But how do I use this to describe the location of D when there is a certain mass hanging at D and there is a certain pulling force in AD?
As I posted, you can use angles θ and φ to write a force balance equation.
 
  • #53
haruspex said:
I was thinking of something simpler, though it may be equivalent: the sine rule.
I used the cosine rule twice to come up with this
 
  • #54
haruspex said:
As I posted, you can use angles θ and φ to write a force balance equation.
So does my post #45 make sense?
 
  • #55
Yes, at least for equilibrium. Adding constant acceleration should be easy.

But I wished you wouldn't change notation every time.
And you can easily simplify ##\ \sin(\pi/2-\pi/4-\phi)\ ## and ##\ \cos(\pi/2-\pi/4-\phi)\ ## I should hope.

So how many equations with how many unknowns do you now have altogether ?
 
  • #56
BvU said:
Adding constant acceleration should be easy.
I believe it is a statics question, how the equilibrium position depends on the applied tension.
 
  • #57
haruspex said:
I believe it is a statics question, how the equilibrium position depends on the applied tension.
The question is: What is the position of the pulley when there is a given mass of the load and a given ratio between the force of gravity and the pulling force.
 
Last edited:
  • #58
Jeroen Staps said:
The question is: What is the position of the pulley when there is a given mass of the load and a given ratio between the force of gravity and the pulling force.
Which is the same as I wrote.
 

Similar threads

  • Introductory Physics Homework Help
Replies
17
Views
1K
  • Introductory Physics Homework Help
Replies
22
Views
3K
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
30
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
19
Views
794
  • Introductory Physics Homework Help
Replies
12
Views
4K
  • Introductory Physics Homework Help
Replies
1
Views
7K
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
980
Back
Top