Describe this very hard integral as a taylor-polynomial

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Homework Statement



Find the polynomal that approximates the integral of (t^2)e^-t^2 from 0 to x, [0,1], with an error less than 10^-3

Homework Equations


You need to use taylor theorem & remainder estimation theorem

The Attempt at a Solution



I set up the tailor series with the first 4 terms (1/e, 0, (2/e)(x-1)^2, (1/6)*(x-1)^4), but where am I supposed to go now? I integrated the series, but I still don't know if I got enough terms.

Hell, what does it mean to integrate something from 0 to x? x isn't even a number! Does the book mean from 0 to 1, since t is an element between 0 and 1? Until I figure what the hell the book is on about, I can't use the remainder estimation theorem.

I am extremely confused atm and I think the book I have is pretty bad at explaining.
 
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x is a number in [0,1]
estimate the function
F(x)=\int_0^x (t^2)e^{-t^2} dt
by another function G(x) such that
|G(x)-F(x)|<10^-3
whenever
0<=x<=1
 
uhm, I'm having trouble finding the error.. I now understand the problem, but I still am unable to use the remainder estimation theorem because:

1) I cannot find M, the biggest value f derived n times, without digital tools. This is because I get increasingly complicated functions as I keep deriving them, and there is no pattern in F(x)'s taylor series.
2) I am a bit unsure on how it works, because I've never used it before.
 
This problem is tedious if done certain ways.

The quick way is to first find the Taylor polynomials of e^x call it p(x) then
(t^2)p(-t^2) is the Taylor polynomial of (t^2)e^-t^2
The error is easily estimated by observing the series is alternating, so the first omitted term is a good estimate of the error.
 
uhm, so it's allowed to just substitute stuff in and out, and multiply the polynomials with t^2? I had no idea... I just wish our professor would be so kind to go through this stuff before the assignments are due.. sigh

Anyway, THANKS allot!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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