I Describing a position vector with polar coordinates.

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In polar coordinates, the position vector is expressed as \(\vec{r} = |r| \hat{r}\), but it requires both radial distance \(r\) and angular component \(\theta\) for a complete description of a point in the plane. The basis vectors \(\hat{r}\) and \(\hat{\theta}\) depend on the angle \(\theta\), making it essential to clarify their relationship to the coordinates. Simply specifying \(r\) without \(\theta\) is insufficient, similar to only providing \(x\) or \(y\) in Cartesian coordinates. The discussion highlights the importance of understanding how to represent vectors in polar coordinates accurately. Overall, both radial and angular components are crucial for a comprehensive representation of position vectors in polar systems.
Mr Davis 97
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I have read that in polar coordinates, we can form the position vector, velocity, and acceleration, just as with Cartesian coordinates. The position vector in Cartesian coordinates is ##\vec{r} = r_x \hat{i} + r_y \hat{j}##. And any choice of ##r_x## and ##r_y## maps the vector to a position in the plane. How is this done with polar coordinates? Online I have read that the position vector in polar coordinates is ##\vec{r} = |r| \hat{r}##, but I don't see how this can map to any point in the plane. Don't we need an angular description as well? I don't see that in this equation.
 
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For position vector, you can always represent a position vector as a sum between a radial vector and angular vector. But the resultant vector turns out to be another radial vector, therefore it's superfluous to use the representation which contains the angular component.
 
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Polar co-ordinates for a plane involve two quantities, 'r' and 'Theta' just like 'x'and 'y' in Cartesian system . If you only specify 'r' then you are not giving the complete picture. It is like mentioning only the 'x' or 'y' in Cartesian co-ordinates.
 
Mr Davis 97 said:
Online I have read that the position vector in polar coordinates is ⃗r=|r|^rr→=|r|r^\vec{r} = |r| \hat{r}, but I don't see how this can map to any point in the plane.
The thing that you have to keep in mind is that in polar coordinates the basis vectors ##\hat r## and ##\hat{\theta}## are functions of the coordinates ##r## and ##\theta##. So ##\vec{r} = |r|\hat{r}## should probably be written ##\vec{r} = |r|\hat{r}_{(r,\theta)}## for clarity.
 
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Dale said:
The thing that you have to keep in mind is that in polar coordinates the basis vectors ##\hat r## and ##\hat{\theta}## are functions of the coordinates ##r## and ##\theta##. So ##\vec{r} = |r|\hat{r}## should probably be written ##\vec{r} = |r|\hat{r}_{(r,\theta)}## for clarity.
Excellent answer. The only thing I would add would be that, in polar coordinates, the two unit vectors are functions only of ##\theta## (and not r).
 
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Chestermiller said:
Excellent answer. The only thing I would add would be that, in polar coordinates, the two unit vectors are functions only of ##\theta## (and not r).
Oops, you are completely correct.
 
So using the notation ##\vec{r} = |r| \hat{r}_{(\theta)}## how would I write out the vector (for example) ##\vec{r} = 2\hat{i} + 4 \hat{j}?##
 
Mr Davis 97 said:
So using the notation ##\vec{r} = |r| \hat{r}_{(\theta)}## how would I write out the vector (for example) ##\vec{r} = 2\hat{i} + 4 \hat{j}?##
What's the angle that the vector <2, 4> makes, and what is its magnitude?
 

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