Describing system in terms of 2 variables vs natural variables

I<3NickTesla
Messages
12
Reaction score
0
Realised I probably posted this in the wrong forum before, should've been here..

I often see a function's differential expressed in terms of convenient partial derivatives eg
dU=(dU/dT) dT + (dU/dV) dV

And I've seen it written that "any system is uniquely specified by two parameters, such as pressure and volume, or perhaps pressure and temperature"

But then what's the deal natural variables? What's so "natural"/good about them if any pair will do? By natural I mean that I've seen the natural variables for gibb's energy as pressure and temperature.
 
Physics news on Phys.org
right, for the Gibbs free energy, the natural variables are pressure and temperature. But there are other thermodynamic potentials than just the Gibbs free energy, and they will have some other natural variables. http://en.wikipedia.org/wiki/Thermodynamic_potential
This website is pretty good. I'll admit that I don't know as much about statistical physics as I would like to know. It is a pretty interesting topic. And then it naturally leads to things like quantum field theories. (i.e. related to renormalisation and phase transitions and symmetry and stuff).
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top