Design a 4.50e-7 C Capacitor w/ 220V & 0.375 m2 Plates

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SUMMARY

The discussion focuses on designing a capacitor that can store a charge of 4.50 × 10-7 C using a 220 V power supply and two metal plates with an area of 0.375 m2. The relevant equation used is V = Q * d / (A * ε0), where ε0 is the permittivity of free space. The calculated maximum plate separation (d) is 1.62E-2 m, although there is a request for verification of this result due to potential calculation errors.

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Homework Statement



You must design a capacitor capable of storing 4.50 × 10-7 C of charge, but you only have a 220- V power supply and two metal plates of area 0.375 m2 each. What is the largest value the plate separation can be so that you can accomplish the task?


Homework Equations



V = Q*d/A*epilson 0

The Attempt at a Solution



I solved for d, and got 1.62E-2 m. Again, don't know what I am doing wrong here.
 
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Hi purduegirl,

That's not quite the answer I get from your equation. Why don't you calculate it again; if you still get the same thing, please show what equation you got when you solved for d and then exactly the numbers you plugged in your calculator.
 

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