Design a Capacitor: 10W, 0.5s, 12V

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    Capacitor Design
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To design a capacitor for starting a small motor, it must deliver an average power of 10W for 0.5 seconds, equating to an energy requirement of 5 joules. The maximum voltage across the capacitor is limited to 12V. The relevant equation for energy stored in a capacitor is u = (1/2)CV², which relates capacitance to voltage and energy. Understanding the physical design, such as using foil plates rolled together, can help optimize size while meeting these specifications. Proper application of these equations will lead to the successful design of the capacitor.
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Homework Statement


You are to design a capacitor capable of providing the energy required to start a small motor. In particular, the capacitor must meet the following three requirements
a) The capacitor must provide an average power of 10W for a time interval of 0.50 seconds
b/ Macimum allowable Capacitor potential difference = 12V

Homework Equations


C = Q/V


The Attempt at a Solution


I am kinda stumped on the average power 10W over 0.5 seconds. Does that mean that i convert back into Energy of 5J or something else?
 
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You're missing a relevant equation. Look for one that defines energy in terms of capacitance and voltage.
 
skeptic2 said:
you're missing a relevant equation. Look for one that defines energy in terms of capacitance and voltage.


u = (1/2)cv² ?
 
That's it.
 
is there an equation or an explanation that will help me understand the values if the plates are a foil and rolled together, so it keeps the area needed at a reasonable size?
 
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