Design Even Number Generator with 4 Bit Counter

AI Thread Summary
To design an even number generator using a 4-bit counter without flip-flops, the simplest method is to implement a left shift operation, effectively multiplying the count by two. This approach ensures that the output remains even by appending a zero bit after the count. Discussions clarify the distinction between a straightforward even number counter and a pseudo-random even number generator, emphasizing the need for clarity in design requirements. Boolean logic equations can also be utilized, but they ultimately simplify to the left shift method. The focus remains on creating a reliable even number generator using the specified constraints.
Nahian
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how can i design an even number generator with a 4 bit counter without using any flip-flop , Using only 4 bit counter?
 
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have it count up, then add a zero bit after the count.
 
Left shift one (as anorlunda says) is the same as multiplying by 2, which is the simplest way to create even numbers.

Were you looking for something different than this?

You can write boolean logic equations to develop a circuit that outputs 2 when you input 1, etc, but it will just reduce to a left shift.
 
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Nahian said:
how can i design an even number generator with a 4 bit counter without using any flip-flop , Using only 4 bit counter?
do you mean an even number generator (a counter), or a (psudo) random even number generator (jumps around to different numbers)?

There is a big difference
 
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