Designing an RC Circuit for RL Equivalent Voltage vs. Time

AI Thread Summary
To design an RC circuit that mirrors the voltage versus time characteristics of a given RL circuit, one must equate the voltage equations of both circuits. The voltage across the capacitor in the RC circuit is described by Vc(t)=Vb(1-e^-(t/RC)), while the current in the RL circuit is given by i(t)=(Vb/R)(1-e^-(tR/L)). The challenge lies in deriving the voltage equation for the RL circuit and transforming it to match the RC format. Participants express confusion about the application of Ohm's law and the proper approach to this problem. Clarifying the relationship between the two circuits is essential for successful design.
dancergirlie
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Homework Statement



Design an RC circuit that has the same Voltage vs. Time characteristics as the RL circuit shown

*See attached Diagram*

Homework Equations





The Attempt at a Solution



Not really sure how to approach this, but all i know is the equations:

RC circuit:

Vc(t)=Vb(1-e^-(t/RC))

RL circuit:
i(t)=(Vb/R)(1-e^-(tR/L))

I really don't know how I'm supposed to use the equation for RL... am I using ohm's law? I am really confused so any help would be great!
 
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hi dancergirlie! :smile:
dancergirlie said:
*See attached Diagram*

where? :cry:
RC circuit:

Vc(t)=Vb(1-e^-(t/RC))

RL circuit:
i(t)=(Vb/R)(1-e^-(tR/L))

now write an equation for V(t) for RL, and get that to look like the V for RC :smile:
 
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