Determination of Grease Viscosity Using Sliding Block Experiment

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The discussion focuses on calculating the viscosity of grease using a sliding block experiment. A small block, weighing 0.15 kg and in contact with a larger block via a 2-micrometre layer of grease, slides down 5 mm over two weeks. The relevant formula involves the relationship between force, area, viscosity, and the change in velocity over the distance of contact. Participants confirm the correct approach by suggesting the use of the provided equation to solve the problem. The calculated viscosity of the grease is determined to be 9.07x10^5 Pa.s.
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Homework Statement


A small block is attached on the left of a larger block by a thin layer of grease, 2 micrometres (10^-6) thick. The mass of the smaller block is 0.15 kg and the area of contact is 8x10^-4 metres squared. If the smaller block slides down 5 mm in 2 weeks, calculate the viscosity of the grease. ANSWER: 9.07x10^5 Pa.s


Homework Equations


A formula which may help is Force/Area = Viscosity(change in velocity)/distances between areas of contact F/A = (n x delta v)/delta x



The Attempt at a Solution


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That looks like the right equation. Try plugging in the information you are given.
 

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