Determine force of water on plate

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To determine the force exerted by water on the orifice plate, the linear momentum equation is applied, considering the pressures at points A and B. The constant velocity of water at 5 m/s and the assumption of incompressibility simplify the calculations. The momentum balance indicates that the rate of change of momentum within the control volume is zero, leading to the conclusion that the inlet and outlet flow rates are equal. The area used for calculations is derived from the dimensions of the orifice. Ultimately, understanding the relationship between pressure, velocity, and force is crucial for solving the problem effectively.
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Homework Statement


As water flows through the pipe at a velocity of 5 m/s, it encounters the orifice plate, which has a hole in its center. The pressure at A is 255 kPa , and at B it is 180 kPa, Assume water is ideal fluid, that is, incompressible and frictionless. Determine the force the water exerts on the plate. Consider the volume of water between A and B as a control volume and apply linear momentum equation.

Homework Equations


F = d/dt ∫ρVdv + ∫Vρ(V•n)dA

The Attempt at a Solution


Well, I have velocity of 5 m/s, which is constant.
The density of the water should remain constant throughout time and space
I have two pressures
The area I used was π(200mm - 75mm)2

But I don't know what to do with volume, the integrals, anything. I don't even know if I'm using the right equation. Is this a Conservation of Energy equation instead? I know that has explicit pressure terms . . . But the problem says linear momentum . . . So do I use ρA + ρA?
 

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To determine the force that the water exerts on the plate, you need to determine the force that the plate exerts on the water. To do that, you need to do a momentum balance. If the inlet and outlet flows and velocities are the same, what is the rate of change of momentum of the fluid in passing through the control volume? What is the net pressure force acting on the fluid in the control volume? What other force is acting on the fluid in the direction of flow?

Chet
 
So are you saying the CS integral will simply be ρV2A, and the other term will be ρV(dv/dt). Since you said a rate of change. And I don't know how to relate explicitly density and velocity to force
 
Bluestribute said:
So are you saying the CS integral will simply be ρV2A, and the other term will be ρV(dv/dt). Since you said a rate of change. And I don't know how to relate explicitly density and velocity to force
The rate of change of momentum within the control surface is zero:

[ρV2A]out-[ρV2A]in=0

So you don't have to know ρ and you don't have to know V.
 
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