There is a 180 pound basketball player. The coefficient of friction between his right foot and the floor is 0.7. There is no acceleration or sliding in the problem. Determine the magnitude and direction of the force that his right foot is exerting on the floor.
ƩF=0 (know what since acceleration is zero)
Ffriction = (0.7)(Fn) (I know Fn is perpendicular to the interface between the two surfaces and it is not equal to the weight of the object. This is what's stated in my physics book.)
Fright foot = -Fgravity - Fn - Ffriction
I would then use component forms of the equation, so one for "x" and one for "y"
The Attempt at a Solution
My attempt at this isn't coming out correctly and I honestly have no idea why.
(for the x equation) (0.7)Fncos0 = Fright footx
(for the y equation) 800sin270 + Fnsin90 = Fright footy
-800 + Fn = Fright footy
I don't know where to go from here, because I'm pretty sure it's already wrong. Any help would be appreciated!