Determine Mass from Net Force, distance, and velocity

AI Thread Summary
A dynamics cart is pulled by a net force of 1.2M, moving 6.6m and reaching a velocity of 3.2m/s. The equation F=ma is used to determine mass, with the initial velocity assumed to be zero. The user initially calculated the mass as 5kg but the textbook states it should be 1.5kg. The correct approach involves using the equation V(final)^2 = V(initial)^2 + 2*a*d to find acceleration. Properly substituting the values should yield the textbook's answer of 1.5kg.
Kupopopo
Messages
1
Reaction score
0
First time in these forums so nice to meet everyone

Homework Statement



A dynamics cart is pulled from rest by a net force of 1.2M [Forward]. The cart moves 6.6m, reaching a velocity of 3.2m/s [Forward].


Homework Equations



F=ma


The Attempt at a Solution



I tried using the formula V(final)^2 = V(initial)^2 + 2*a*d to get acceleration and plug it into F=ma to find mass and got 5kg but the textbook says that the answer is 1.5kg
 
Physics news on Phys.org
I assume vi = 0 in your calculation so that vf^2 = 2 . a . d with d=6.6m

what did you get for a?

given a you should get what your book says.
 
Possibly you made an error in your calculations. As jedishrfu said, if you plug in all the known values in, you should get 1.5kg no problem.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top