(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Determine the threshold energy for electrons to produce Cerenkov radiation in glass (refractive index n=1.52).

3. The attempt at a solution

The only equations given in my notes are:

cos [itex]\theta[/itex][itex]_{C}[/itex]=1/[itex]\beta[/itex]n for [itex]\beta[/itex]>1/n

and

dN/d[itex]\lambda[/itex]=[itex]\frac{2\pi\alpha}{\lambda^{2}}[/itex]L sin[itex]^{2}[/itex] [itex]\theta[/itex][itex]_{C}[/itex]

How the second equation relates to the energy, I don't know. What does dN/d[itex]\lambda[/itex] have to do with the energy? And how is the 'threshold' supposed to be worked out?

Is E=mc[itex]^{2}[/itex] in this case? Is the energy supposed to be deduced from [itex]\lambda[/itex]?

Please help.

My textbooks and the internet don't tell me know to do this sort of question either.

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# Homework Help: Determine the threshold energy for electrons to produce Cerenkov radiation in glass

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