Determine Vo for the following network.

  • Thread starter Thread starter HebrewHammer
  • Start date Start date
  • Tags Tags
    Network
Click For Summary

Discussion Overview

The discussion revolves around determining the output voltage (Vo) for a given electrical network, with a focus on applying Kirchhoff's Voltage Law (KVL) and analyzing the circuit behavior under varying conditions. The context includes homework-related problem-solving and circuit analysis.

Discussion Character

  • Homework-related, Technical explanation, Debate/contested

Main Points Raised

  • One participant mentions needing to use KVL to find Vo and expresses difficulty in reaching the answer provided by a classmate.
  • Another participant suggests that the output should be time-varying due to a time-varying input voltage and proposes modeling the diode as a voltage source, recommending the principle of superposition for analysis.
  • A different participant claims to have found a solution by applying KVL, calculating a voltage across a capacitor and proposing a value for Vo based on their analysis.
  • Another participant challenges the previous claim, indicating that the analysis must account for changes in the input voltage.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus, as there are competing views on the correct approach to determine Vo and the implications of input voltage changes.

Contextual Notes

There are unresolved assumptions regarding the behavior of the circuit under varying conditions, and the calculations presented may depend on specific interpretations of circuit elements and configurations.

HebrewHammer
Messages
8
Reaction score
0

Homework Statement



Determine Vo for the following network

[PLAIN]http://img535.imageshack.us/img535/7041/63014601.jpg.

Homework Equations



Too many to list I would think. I'm pretty sure I have to use KVL.

The Attempt at a Solution



My classmate told me the answer was 2.45V. I can't for the life of me get even close to this. I need some fresh ideas.
 
Last edited by a moderator:
Physics news on Phys.org
There is a time-varying input voltage, so the output should also be time-varying. (At least in this case.) It could be useful to model the diode as a voltage source. You could use the principle of superposition to find the voltage over the resistor...
 
Think I got it,

Applying KVL

-20 + Vc - 5 = 0
Vc = 25V

The capacitor is charged up to 25 V.
Thevenin equivalent ckt of that portion of the network which includes Battery and resistor will result in RTH = 0Ω and ETH = V = 5V.

For the period t₂-t₃
Applying KVL
10V + 25 - v₀ = 0
v₀ = 35 V

What do you think?
 
Almost right.

You need to consider what will happen when the input changes.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
7K
Replies
8
Views
2K
Replies
6
Views
3K
Replies
50
Views
5K
  • · Replies 40 ·
2
Replies
40
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
8K
Replies
5
Views
2K