Determine whether germanium is a conductor at a certain frequency

AI Thread Summary
To determine if germanium is a conductor at 2.4 GHz, the conductivity (sigma) of 2.3 is used alongside the frequency to calculate the angular frequency (omega) as 1.507 x 10^10. The permittivity (epsilon) is found to be 1.526 x 10^-10, leading to a relative permittivity (epsilon_r) of 17.24. The time constant, calculated as epsilon/sigma, indicates the material's conductivity; a short time constant suggests good conductivity. The final relative permittivity value of 17.24 supports the conclusion that germanium behaves as a conductor at this frequency.
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Homework Statement


Determine, whether germanium (sigma=2.3) is a conductor at the frequency of 2.4 GHz.
sigma=?(omega)(epsilon)


Homework Equations





The Attempt at a Solution


Well I know omega=2∏f and I have f. Thus I could find omega. Given sigma I could find epsilon but what excatly does that tell me about it being a conductor? hen this is done I get epsilon to be 1.526e-10
 
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I could find for a time constant epsilon/sigma and if it is short I will know it is a good conductor is that ok?
 
I got the relative epsilon to be 17.24
 
ω=2∏f=2∏(2.4x10^9)=1.507x10^10
σ=2.3
σ=ωε
ε=1.526x10^-10
ε0εr=1.526x10^-10
εr=(1.526x10^-10)/(8.85x10^-12)=17.24
my final answer is 17.24 am I good?
 
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