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Determing if a function with integral within it is even/odd

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  1. Nov 10, 2015 #1
    1. The problem statement, all variables and given/known data
    Determine if the function is even/odd/neither without solving the integral

    2. Relevant equations
    [tex] f(x)=\arctan (x)-2\int_0 ^x{\frac{1}{(1+t^2)^2}}[/tex]

    3. The attempt at a solution
    I tried to do f(-x)-f(x). I know that if f is odd, I should get -2f(x) and if even, 0. I got that f is odd(-2f(x)), but I don't know if this is a correct answer, since wolfram alpha says that this is not an odd function. I didn't assume anything on the function while checking this. I am a bit confused.
    Is there any way to check things like that?

    Thank you,
    Thomas
     
  2. jcsd
  3. Nov 10, 2015 #2
    When the limits of the integration are 0 to x, the integral of an even function is odd and the integral of an odd function is even.
    Look at each term in the equation. If each part is even, then the whole thing is even. Same with odd. But if you add an even and odd function (that are not 0) then you get neither.
     
  4. Nov 10, 2015 #3

    HallsofIvy

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    First you know that arctan(x) is an odd function, right? Further, making the change of variable, u= -t in the integral, so that dt= -du
    [tex]\int_0^x \frac{dt}{(1+ t^2)^2}[/tex]
    becomes
    [tex]\int_0^{-x}\frac{-du}{(1+ (-u)^2)^2}= -\int_0^{-x} \frac{du}{(1+ u^2)^2}[/tex]
    changing the "dummy variable", u, in that integral to t,
    [tex]\int_0^x \frac{dt}{(1+ t^2)^2}= -\int_0^{-x} \frac{dt}{(1+ t^2)^2}[/tex]
     
  5. Nov 10, 2015 #4
    Hi,
    First, thank you for the answer.
    How do we know that the integral of an odd function is even and the same with even function? Maybe I will try to prove it, but expect to a question about that :)

    Second, since the integrand is even, that means(according to you, but I am still not convinced about it) that the integral is odd. And since arctan is odd, that means that the whole function is odd. Right?
     
  6. Nov 10, 2015 #5

    epenguin

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    HoI essentially just answered your question in #4. He did it for the particular function, but you could write out the proof again for integral of any function f which satisfies the condition of evenness which you should write out. The key point which you may have missed in the detail is, and may even disbelieve till you think about it :oldsmile: is, to say it crudely

    ab = - ∫ba
     
  7. Nov 10, 2015 #6
    Thank you. I did something similar with the function but without changing the variable.

    As I said to HallsofIvy, I did the same thing. I just assumed that without loss of generality, x is positive then -x is negative and you flip the limits of the integral and you add minus.

    I cannot see those things/"proofs" in my head without write them. That might be the reason I was( well, and still a bit) sceptical(Well, I am studying mathematics, I guess I should be sceptical).

    So, I understand that my answer is correct :)

    Thank you all.
     
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