Determining ansatz for forced oscillations in SHM

Click For Summary
SUMMARY

The discussion focuses on the use of an ansatz for solving forced oscillations in simple harmonic motion (SHM), specifically referencing the Feynman Lectures on Physics. The proposed solution for a damped oscillator is given by $$x = \hat{x}e^{iwt}$$, derived from the differential equation $$m \ddot{x} + c \dot{x} + kx = F_0 \cos{wt}$$. Participants explore the rationale behind this ansatz, emphasizing its suitability for scenarios involving forced oscillations and the underlying mathematical principles that validate its use.

PREREQUISITES
  • Understanding of second-order differential equations
  • Familiarity with the concepts of forced oscillations and damping
  • Knowledge of complex exponentials and their relation to trigonometric functions
  • Experience with linear ordinary differential equations (ODEs)
NEXT STEPS
  • Study the derivation of solutions for damped oscillators in classical mechanics
  • Learn about the method of undetermined coefficients in differential equations
  • Explore the application of Fourier series in solving differential equations
  • Investigate the role of complex numbers in oscillatory motion analysis
USEFUL FOR

Students and professionals in physics, particularly those studying mechanics and oscillatory systems, as well as mathematicians interested in differential equations and their applications in real-world scenarios.

etotheipi
I've generally solved introductory second order differential equations the 'normal' way; that is, using the auxiliary equation, and if it is inhomogeneous looking at the complementary function as well, and so on.

I know that sometimes it can be helpful to propose an ansatz and substitute it into determine unknown coefficients. In this section of the Feynman lectures (http://www.feynmanlectures.caltech.edu/I_23.html) he proposes a solution to a damped oscillator with forced oscillations of the real part of $$x = \hat{x}e^{iwt}$$where the original differential equation was$$m \ddot{x} + c \dot{x} + kx = F_0 \cos{wt}$$How has he determined that this is a suitable ansatz for the scenario? Is this particular ansatz only applicable when forced oscillations are involved (excluding the obvious simplest case with no damping or periodic force)?N.B. I am not concerned about the complex exponential, the real part of which is \cos{\omega t}, but more why this expression has been deemed suitable for the case with forced oscillations (though of course it does actually work, and we could also obtain a solution of that form from first principles of differential equations).

Thank you!
 
Last edited by a moderator:
Physics news on Phys.org
etotheipi said:
I've generally solved introductory second order differential equations the 'normal' way; that is, using the auxiliary equation, and if it is inhomogeneous looking at the complementary function as well, and so on.

I know that sometimes it can be helpful to propose an ansatz and substitute it into determine unknown coefficients. In this section of the Feynman lectures (http://www.feynmanlectures.caltech.edu/I_23.html) he proposes a solution to a damped oscillator with forced oscillations of the real part of $$x = \hat{x}e^{iwt}$$where the original differential equation was$$m \ddot{x} + c \dot{x} + kx = F_0 \cos{wt}$$How has he determined that this is a suitable ansatz for the scenario? Is this particular ansatz only applicable when forced oscillations are involved (excluding the obvious simplest case with no damping or periodic force)?N.B. I am not concerned about the complex exponential, the real part of which is \cos{\omega t}, but more why this expression has been deemed suitable for the case with forced oscillations (though of course it does actually work, and we could also obtain a solution of that form from first principles of differential equations).

Thank you!
Not entirely sure I understand your question, but I believe mathematicians looked at the linear ODE structure and thought what function, if differentiated, can be summed to be itself? The answer is, of course, a series solution taking the form ##\sum_i a_i x^i## where the coefficients ##a## are to be determined. This makes sense, right? Consider the homogenous solution to the undamped system ##\ddot x + k/m x = 0##. Guessing $$y = \sum_ia_i x^i = a_0 + a_1x + a_2x^2+a_3x^3+... \implies\\
y''=2a_2+6a_3x+... \implies\\
\ddot x + \frac k m x = 0 \implies\\
2a_2+6a_3x+... + \frac k m (a_0 + a_1x + a_2x^2+a_3x^3+...) \implies\\
(2a_2+\frac k m a_0) + (6a_3 + a_1)x + ... = 0 + 0x \implies\\
2a_2+\frac k m a_0 = 0,\,\,\, 6a_3 + a_1 = 0$$

(sorry, my ##x##'s should be ##t##'s and my ##y##'s should be ##x##'s, but you get the idea.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 25 ·
Replies
25
Views
6K
  • · Replies 3 ·
Replies
3
Views
1K