Determining electric field at origin from semicircle charge

AI Thread Summary
To determine the electric field at the origin from a semicircular charge distribution, the electric field contribution from each charge element must be considered. The direction of the electric field is towards the origin, which is why it is represented as -r hat. The total enclosed charge is calculated as the product of the linear charge density and the semicircle's radius, leading to the expression (ρl)(b). The arc length at radius b is essential for integrating the contributions of the electric field from the entire semicircle. Understanding these concepts is crucial for accurately applying the principles of electrostatics to this problem.
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Homework Statement


A line of charge of uniform density ρl occupies a semicircle of radius b as shown in Fig. P4.10. Use the material presented in Example 4-4 to determine the electric field at the origin.

Homework Equations


dE = kdQ/r^2

The Attempt at a Solution


I'm trying to understand the solution given in the solutions manual, here it is:

http://www.zmuda.ece.ufl.edu/Fields_1_Spring 2013/4-1.10.pdf

1. Why is the direction -r hat, rather than just r hat?
2. Why is the enclosed charge Q stated as (pl)(b)? Shouldn't it be pl multiplied by the arc length of the half circle? I understand that I'm wrong and the solution is right, but I do not understand why the charge density would be multiplied by the radius.
 
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1. The electric field felt at the origin due to the charge ##dE## at position ##\hat{\mathbf{r}}## points from ##\hat{\mathbf{r}}## toward the origin. (Recall that a positive ##dE## would exert a repulsive force on a positive test charge at the origin.)

2. What is the arc length at radius ##b## that subtends the angle ##d\phi##?
 
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