Determining Final Velocity of an Electron Absorbing an X-ray?

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    Compton effect
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The discussion revolves around calculating the final velocity of an electron after absorbing an X-ray with a wavelength of 2.5 x 10^-8 m. The initial attempt used a formula for conservation of momentum, but there were errors in the mass of the electron and the assumption of an elastic collision. It was clarified that a solitary electron cannot absorb a photon in the way described, and if it were to interact, it would involve the Compton effect, where the photon scatters rather than being absorbed. The correct approach requires addressing the inelastic nature of the interaction and ensuring accurate values for constants. The conversation highlights the need for precise understanding of particle interactions in physics problems.
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Hey, I was just wondering if someone could give me feedback on a problem. For some reason the answer is not in the back of the text.

Homework Statement



An x-ray with a wavelength of 2.5 x 10-8 m is absorbed by a stationary electron. Determine the final velocity of the electron.
Vxray=3.0x10^8 m/s
Velectron=0
melectron= 1.602x10^-19kg
mxray=(h/λc)
Velectron(after)=
h=6.626x10^-34Js
λ=2.5x10^-8

Homework Equations


Velectron(after)= Vxray((2(h/cλ))/(melectron+(h/cλ)))

The Attempt at a Solution



V(electronafter)= (3.0x10^8)((2((6.626x10^-34)/(3.0x10^8)(2.5x10^-8))/(1.602x10^-19)((6.626x10^-34)/(3.0x10^8)(2.5x10^-8)))

v(electronafter)= 3.31x10^-7m/s

Sorry if the formula is hard to understand, I used the formula for conservation of momentum in an elastic collision where one object is stationary before the collision.
 
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Your problem statement doesn't mention a proton. How does it come into the problem?
 
Sorry anywhere it says proton it should say electron.
 
A solitary electron cannot absorb a photon. (Also if it did, it would be an inelastic collision, not an elastic collision.) If this problem is about the Compton effect, the photon scatters off the stationary electron.

Your value for the mass of the electron isn't correct.
 
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