Determining if Final Value Exists for Final Value Theorem

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The discussion centers on the application of the final value theorem, which states that the limit of sF(s) as s approaches 0 equals the limit of F(t) as t approaches infinity, provided that a final value exists. To determine if a final value exists, one can analyze the poles of the transfer function; a stable system will converge to a specific value, while an unstable system will diverge. The theorem can be used to verify if the time function converges to a real value by solving lim sF(s) for s->0. If this limit exists, it indicates that the transfer function is valid and the results from both limits will match. This approach simplifies the analysis, as many terms cancel out when evaluating the limit as s approaches 0.
salman213
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I had a question about the final value theorem:

lim sF(s)
S->0

=

lim F(t)
t->infinity


I was told I can only use this if I know that a final value exists for f, or in other words that f(infinity) exists.

How can I check if it exists? If I have F(s), the only way I can think to check is to find the inverse Laplace and then see. If I do that, then there is no use of me applying the final value theorem as I will already know what it is.

Can some explain how one can determine whether or not the final value exists before applying the theorem?

Thanks!
 
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Well, if you have the transfer function of a system, by analyzing the poles you can determine whether the system is a stable or an unstable one. Giving an appropriate input to a stable system results in an output response that converges to a particular value as t tends to infinity while for an unstable system the output goes to infinity (i.e. it is not bounded)
 
I think you USE the final value theorem to verify IF the time function converges to a real value. Basically you solve lim sF(s) for s->0, and if this value exists then the transfer function is good and works because lim sF(s) for s->0 = lim f(t) for t->infinity. If the transfer function is good you would get the same value when solving either limit(if you know the time function). The difference would be that solving lim sF(s) for s->0 is easier because many terms of the transfer function will cancel out because of the s->0.

Hope you got it!
 

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