Determining Planck's Constant Using Diffraction Patterns of X-rays and Electrons

AI Thread Summary
The discussion focuses on determining Planck's constant using diffraction patterns from X-rays and electrons, which are found to be identical. The relationship L = h/p is central, where L is the wavelength, h is Planck's constant, and p is momentum. The momentum of electrons is calculated using their energy of 688eV, applying the formula E = (p^2)/2m. Converting the X-ray wavelength of 46.8pm to SI units allows for the calculation of Planck's constant. The identical diffraction patterns imply that both particles share the same wavelength, reinforcing the validity of the calculations.
Steph
Messages
11
Reaction score
0
I'm stuck on the following question:

the diffraction patterns produced when Xrays of wavelength 46.8pm or electrons of energy 688eV are scattered from the same specimen of aluminium are found to be essentially identical. Use this information to determine the value of Planck's constant, h.

I'll let L = wavelength, p = momentum

So far I've calculated the momentum of the electrons using E = (p^2)/2m. I also have converted the Xray wavelength to SI units.

So I know L = h/p thus h = Lp = constant. But I'm not sure what to do from here. Does the fact they have the same diffraction pattern mean that the wavelength of the X-rays is equal to that of the electron beam?

Thanks for any hints you can give me
 
Physics news on Phys.org
Sorry - I've just found the mistakes in my working and have managed to complete the question :blushing:
 
.

To determine Planck's constant using diffraction patterns of X-rays and electrons, we can use the equation L = h/p where L is the wavelength, h is Planck's constant, and p is the momentum. In this case, we have two different particles (X-rays and electrons) with the same diffraction pattern, which suggests that they have the same wavelength.

First, we can calculate the momentum of the electrons using the given energy of 688eV. We know that the kinetic energy of the electrons is given by E = (p^2)/2m, where m is the mass of the electron. Rearranging this equation, we can solve for the momentum p: p = √(2mE).

Next, we can convert the X-ray wavelength of 46.8pm to SI units (meters) and use this value for L in the equation L = h/p. This will give us a value for h, which is the Planck's constant.

However, in order to get a more accurate value for h, it would be best to repeat this experiment with different X-ray wavelengths and electron energies to ensure that the diffraction patterns are still identical. This will help to eliminate any potential errors or inconsistencies in the data.

Overall, the fact that the X-rays and electrons have the same diffraction pattern suggests that they have the same wavelength, which can be used to determine the value of Planck's constant using the equation L = h/p.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top