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Determining scale readings given different densities

  • #1
Connected by a string to a scale is an object and when suspended in air, the scale reads 200 N. The scale reads 150 N when the object is suspended in water (d = 1000 kg/m^3). What does the scale read (in N) when the object is suspended in oil having a density of 800 kg/m^3?

I determined that the volume of the object was .015 m^3 from using the d=m/v formula in the H2O portion of the problem. I just substituted the volume into the oil density and determined that the mass was 12.24 kg. and then converted that to 120 N. Did I do this correctly?
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
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I determined that the volume of the object was .015 m^3 from using the d=m/v formula in the H2O portion of the problem.

Loss of weight in liquid is equal to the weight of the displaced liquid.
In the problem loss of weight in water is 50N. Then what is the volume of the object?
 

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