Determining the number of subgroups

[duki]

Homework Statement

How many subgroups does //567,000 have? (don't know the smart-text for a group)

Homework Equations

The Attempt at a Solution

From the notes I'm looking at, he did something like
2^3 * 3^4 * 5^3 * 7 = 567,000
and somehow this equates to 128 subgroups.

I have no clue how he came to this though... could someone give me a hand on finding the number of subroups in a group?

 

[Dick]

You mean the cyclic group Z_567000, yes? It's just the number of divisors of 567000. I don't think it's 128. How many are there?

 

[duki]

Thanks for the reply!

I'm not exactly sure how to find the number of divisors... I think there's a way to do something with the primes, but I never really understood it.

 

[Dick]

The number of divisors is the number of integers of the form 2^i*3^j*5^k*7^l. i is in {0,1,2,3}, j is in {0,1,2,3,4} etc. Do you get my drift? Each choice is a different number because of unique prime factorization. How many are there?

 

[duki]

I still don't understand =(
Maybe if we used a smaller number for me to get the hang of it? sorry

 

[Dick]

Ok. How many divisors of 12? 12=2^2*3^1. So the divisors are 2^i*3^j where i is in {0,1,2} and j is {0,1}. That's 3 choices (for i) times 2 choices (for j)=6. And that is the number of divisors of 12, right? Same idea for 567000.

 

[duki]

So for 567,000 I'm getting:

2^3 * 3^4 * 5^3 * 7 = 210 subgroups?

 

[Dick]

No. How did you get 210?

 

[duki]

2 * 3 * 5 * 7 ? =/

 

[Dick]

http://mathworld.wolfram.com/Divisor.html Expression (5).