Determining Time for Nut to Go Through Taper with Oversizing Machine

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The discussion revolves around calculating the time required for a 1/2 inch hexagonal nut to pass through a 100 mm taper using an oversizing machine. The user provides details such as the pressure of 3.5 kg/mm², machine power of 5 HP, and attempts to solve the problem using equations related to force, work, and power. Despite following the calculations, the user expresses dissatisfaction with the final time result of 205 seconds and seeks validation or corrections on their approach. There is also a request for guidance on whether additional factors like angular velocity or torque should be considered in the calculations. The user emphasizes the importance of this problem and is eager for feedback or assistance from the community.
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1st of all please give me some guidance since I am a new here and please remind me if I am do wrong in term of my wrongly area of posting, i just want to make some freinds and to share the knowledge wif all of u guys, thanks for supporting and thanks for all ur help and guide

thanks agains

Homework Statement

http://img216.imageshack.us/img216/20/22129520.png
i need ur help regarding this, I've tried by my self but I am soo sure that I've done wrongly

here it comes
the figure shows that how i oversizing the hex 1/2" nut by oversizing machine. the pressure which is 3.5kg/mm sq is push the nut thru the tapper of a 100 mm length. how can i determine the time taken,t for the nut to going thru the 100mm tapper

here is the detail that may required

size of nut: 1/2 inch hexagonal nut (internal dia of nut = 1/2 inch)
pressure, P: 3.5kg/mm sq
tapper length,L: 100mm
Power of machine: 5HP
Speed: 750 rpm
time, t = ?i

Homework Equations



when I am try to solve the problem, I am using this equation
1. P=Fa (find F)
2. W=F x S (find W) work = f x s
3. P= W/ t (find t) power = w/t

The Attempt at a Solution



ive once try to determine the force exist by P=F/A:
then once i get the F, I've determine the work done by W=F x S;
lastly I've tried to find the time,t by using P= W/t which is P is a power of machine while W is a work done

but I am not satisfied with the answer that i got,

here is my work

1st. To find area of 1/2” inch hex nut (im not sure if it is correct)

area of hex nut?? = 6as + Ph
= 6(2)(1.2) + 7.2 (1.1)
= 22.32cm

wheres a= apothem length
s= side length
perimeter of the base= 6 * s
= 6 * (1.2)
= 7.22nd. Find Force, F

(converting 3.5kg/mm sq into unit pascal I got 34.3MPa)P=F/A
F=PA
=34.3Mpa * (22.32 x 10-2)

F= 7.66 x 106 N3rd. Det work done

W = F * S
= 7.66 x 106 (100 x 10-3)

W= 765.6 x 103 N
4th find time, t

P=W/t
t=W/P

where p= power of machine =5HP = 3730 watt ?

t=765.6 x 103 N / 3730

final answer; t=205 sec ?
can anybody correct me if I am wrong or giving me for some tips or correct formula on how to done iti would very great of any possible idea and i'll tried by myself before refer to all of u back

if u hv any question or didnt understand wif the question, please ask me and i would really great to explain

thanks again

regards
 
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is it i need to consider such as angular velocity or torque or anything that i misconsidered?
 
thanks 4 those who r viewing my thread, i still hv no idea wif this question except for my trial solution, any idea would be please
 
still hv no idea mates?
im might be offline for a while and i'll update any of ur question (if have) later and i will because this is quite important to me

thanks mate
 
anybody?need ur favor and thanksp/s:if I am done it in wrong section or maybe my way is a bit annoying pls to let me know as i can manage myself to do it rite
 
:cry::cry:
 
can i know why am i didnt get any reply?
is it I am do it in wrong way?
 
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