Determining velocity of frame in spacetime

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To determine the velocity of an observer seeing two spacelike events simultaneously, the spacetime interval equation is used, where the difference in time and distance is analyzed. The initial calculations yield a distance of 4 meters when the time is set to 0 in the new frame. The observer's velocity is found to be v = 0.6 using the stretch factor equation, but the discussion seeks a more straightforward method to arrive at this result. Additionally, clarification is requested on how to determine the correct value of gamma (4/5 or 5/4) based on length contraction. Understanding these concepts is crucial for accurately analyzing spacetime intervals in relativity.
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I have a short question regarding a spacetime interval in relativity.

I am told that event 1 is 2 meters of time and 1 meter of distance from the origin. Event 2 is 5 meters of time and 6 meters of distance from the origin. The question asks me to find the velocity of an observer that sees these events at the same time since they are spacelike (as opposed to timelike).

I began by using the equation \Delta{t^2}-\Delta{x^2}=\Delta{t^2}-\Delta{x^2} Using the measurements from the rest frame gives me 3^2-5^2=\Delta{t^2}-\Delta{x^2}

I know that t should be 0 in the new frame, giving me d = 4. So my question is, how can I use this information to determine the velocity of this new frame?
 
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Well, I just found the answer using the equation for the stretch factor but is there a more direct way of obtaining the correct answer of v=.6?

EDIT: One more thing. When using the stretch factor equation of \gamma=\frac{1}{(1-v^2)^{1/2}}, how do I know whether gamma is 4/5 or 5/4 by looking at the length contraction in this problem?

Thanks
 
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