Did I Properly Answer the Angular Resolution Question?

AI Thread Summary
The discussion confirms that the methodology used to answer the angular resolution question is correct, particularly the application of the formula θ=1.22 (λ/D). However, there is uncertainty regarding the selection of typical wavelengths, as the GMRT operates across a wide frequency range. While 1 m is considered a reasonable ballpark figure, it is noted that radio wavelengths larger than 10 m may be blocked by the atmosphere. The choice of optical wavelength at 500 nm is also acknowledged as a typical value, though it represents a narrower range. Overall, the approach and usage of the formula are deemed appropriate, but clarity on wavelength selection is needed.
shanepitts
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Homework Statement


1.3.png


Homework Equations


θ=1.22 (λ/D)

The Attempt at a Solution


1.3 answer.jpg

Just want to know if I properly answered this question.

Thanks in advance
 
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Yes, your methodology is correct.

The only thing I can not confirm is how you are expected to choose the typical wavelengths involved. The GMRT is capable of operating on many frequencies in different bands -- altogether the range is greater than an order of magnitude from highest to lowest wavelength. Although yes, 1 m is within that range, if you're just looking for a ballpark figure.

Similarly, we can say the same thing about the optical wavelength (where 500 nm is typical), although it is a much narrower range (much less than 1 order of magnitude).

So anyway, I'm guessing that your approach is fine. Your usage of the formulae is good. I think your choices of wavelengths are good for ballpark figures, but I can't say for sure that you are supposed to be looking for ballpark figures.
 
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collinsmark said:
Yes, your methodology is correct.

The only thing I can not confirm is how you are expected to choose the typical wavelengths involved. The GMRT is capable of operating on many frequencies in different bands -- altogether the range is greater than an order of magnitude from highest to lowest wavelength. Although yes, 1 m is within that range, if you're just looking for a ballpark figure.

Similarly, we can say the same thing about the optical wavelength (where 500 nm is typical), although it is a much narrower range (much less than 1 order of magnitude).

So anyway, I'm guessing that your approach is fine. Your usage of the formulae is good. I think your choices of wavelengths are good for ballpark figures, but I can't say for sure that you are supposed to be looking for ballpark figures.
Thank you for your detailed response
 
I think radio wavelengths larger than 10m are blocked by the atmosphere.
 
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