When question is asked: "How close is the slope (from an X-t graph) you calculated and the value actually displayed on the graph?"---does this mean you simply subtract your calculated velocity(slope of X-t graph) from the slope actually given on the graph?
your calculated slope is 0.2460 met./sec.
the slope given on the graph is 0.2487 met./sec
So, the difference between these should be 0.2487 - 0.2460 = 0.0027 units??
The Attempt at a Solution
i am unsure if i need to use the percent error formula or just simply subtract the two slopes to get the difference. actually, i am unsure of when you are supposed to use the percent error formula. Does the percent error formula have anything to do with this particular problem?