Differential cross section/simple integral

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Homework Help Overview

The discussion revolves around integrating a differential cross section in the context of particle physics, specifically focusing on the integration over angles theta and phi to retrieve the total cross section, sigma(naught).

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the integration process and the substitutions needed for the differential elements. There are attempts to clarify the correct form of the differential solid angle and the resulting integrals.

Discussion Status

Some participants have provided guidance on the correct substitutions and integration steps, while others express uncertainty about their approaches and results. There is an ongoing exploration of the mathematical reasoning behind the integration process.

Contextual Notes

Participants are navigating through potential misunderstandings regarding the use of differential elements in the integration process, with some expressing confusion over the appearance of logarithmic terms in their results.

jonwell
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At least it should be a simple integral...

Homework Statement



The whole text is here- http://i35.tinypic.com/2nisnp.jpg

Basically (I think) I need to integrate the differential over all angles theta and phi, and get sigma(naught) back out.


Homework Equations



given in pic

The Attempt at a Solution



If I use the given substitution and integrate I get log(tan(pi/2)) which is log(0) which is broken... I don't really know where to go other than that.

Thanks! Been reading the forum for a long time but this is my first question :)
 
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You shouldn't be getting any Log terms when you integrate; if you show me your work, I can tell you where you are going wrong.
 
I substitute sin(theta) for d(omega), and the integral for 1/sin(theta) is log(tan(theta/2)) at least as given by mathematica and the back of my book.

I kind of figured I shouldn't be getting that, which is what makes me think I'm approaching the problem all out of whack.
 
You should be substituting sin(\theta) d \theta d \phi for d \Omega not just sin(\theta)...d \Omega is a differential, sin(\theta) is just a function...you should have:

\frac{d \sigma}{d \Omega}=\frac{d \sigma}{sin(\theta) d \theta d \phi}=\frac{\sigma_0}{4 \pi}

\Rightarrow d \sigma=\frac{\sigma_0}{4 \pi} sin(\theta) d \theta d \phi

...do you follow?

Then just integrate both sides of the equation.
 
gabbagabbahey said:
You should be substituting sin(\theta) d \theta d \phi for d \Omega not just sin(\theta)...d \Omega is a differential, sin(\theta) is just a function...you should have:

\frac{d \sigma}{d \Omega}=\frac{d \sigma}{sin(\theta) d \theta d \phi}=\frac{\sigma_0}{4 \pi}

\Rightarrow d \sigma=\frac{\sigma_0}{4 \pi} sin(\theta) d \theta d \phi

...do you follow?

Then just integrate both sides of the equation.


I figured it was something simple. I follow perfectly, thank you very much :)

[...I need to figure out that LaTeX code stuff, that's pretty cool.]
 
Your welcome. There's an introduction to LaTeX here :smile:
 

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