Differential cross section/simple integral

AI Thread Summary
The discussion revolves around integrating the differential cross section to retrieve the total cross section, sigma(naught). The user initially struggles with obtaining a logarithmic term during integration, which indicates a potential misstep in their approach. It is clarified that the correct substitution involves using sin(theta) d theta d phi for the solid angle differential, d Omega. The correct relationship is established as d sigma equals sigma_0 over 4 pi multiplied by sin(theta) d theta d phi. The user acknowledges the guidance and expresses appreciation for the clarification.
jonwell
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At least it should be a simple integral...

Homework Statement



The whole text is here- http://i35.tinypic.com/2nisnp.jpg

Basically (I think) I need to integrate the differential over all angles theta and phi, and get sigma(naught) back out.


Homework Equations



given in pic

The Attempt at a Solution



If I use the given substitution and integrate I get log(tan(pi/2)) which is log(0) which is broken... I don't really know where to go other than that.

Thanks! Been reading the forum for a long time but this is my first question :)
 
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You shouldn't be getting any Log terms when you integrate; if you show me your work, I can tell you where you are going wrong.
 
I substitute sin(theta) for d(omega), and the integral for 1/sin(theta) is log(tan(theta/2)) at least as given by mathematica and the back of my book.

I kind of figured I shouldn't be getting that, which is what makes me think I'm approaching the problem all out of whack.
 
You should be substituting sin(\theta) d \theta d \phi for d \Omega not just sin(\theta)...d \Omega is a differential, sin(\theta) is just a function...you should have:

\frac{d \sigma}{d \Omega}=\frac{d \sigma}{sin(\theta) d \theta d \phi}=\frac{\sigma_0}{4 \pi}

\Rightarrow d \sigma=\frac{\sigma_0}{4 \pi} sin(\theta) d \theta d \phi

...do you follow?

Then just integrate both sides of the equation.
 
gabbagabbahey said:
You should be substituting sin(\theta) d \theta d \phi for d \Omega not just sin(\theta)...d \Omega is a differential, sin(\theta) is just a function...you should have:

\frac{d \sigma}{d \Omega}=\frac{d \sigma}{sin(\theta) d \theta d \phi}=\frac{\sigma_0}{4 \pi}

\Rightarrow d \sigma=\frac{\sigma_0}{4 \pi} sin(\theta) d \theta d \phi

...do you follow?

Then just integrate both sides of the equation.


I figured it was something simple. I follow perfectly, thank you very much :)

[...I need to figure out that LaTeX code stuff, that's pretty cool.]
 
Your welcome. There's an introduction to LaTeX here :smile:
 
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