Differential Equation mixing problem!!!!! 1. The problem statement, all variables and given/known data A vat with 500 gallons of beer contains 4% alcohol (by volume). Beer with 6% alcohol is pumped into the vat at a rate of 5 gal/min and the mixture is pumped out at the same rate. What is the percentage of alcohol after an hour? 3. The attempt at a solution This is what ive been doing. dA/dt = inflow - out flow = (.06)(5) - (A/500)(5) = .3 - (A/100) = (30 - A)/100 etc but I feel I must be setting it up wrong or something ?? But it never gets the correct answer which is. 4.9% If anyone can point out whats up that would be much appreciated!