Differential Equations: Second Order Equations

peace-Econ
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Homework Statement



Find a second order differential ewuation for which three functions y=2e^-t, y=2te^-t, y=e^(-t+1) are solutions.

Homework Equations





The Attempt at a Solution

 
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Since you didn't show us what you have tried, instead of answering your question directly, I will ask you this:

Can you solve this de:

y'' - 4y' + 4y = e2t

and if so, what method would you use?

Hint: This isn't an idle question.
 
peace-Econ said:

Homework Statement



Find a second order differential ewuation for which three functions y=2e^-t, y=2te^-t, y=e^(-t+1) are solutions.

Homework Equations





The Attempt at a Solution

If those functions were independent, this would be impossible but e^{-t+ 1}= e^{-t}e^1= e e^{-t}, a constant times e^{-t} so you really have only two independent solutions.

Do you know what the "characteristic equation" of a linear differential with constant coefficients is? Such an equation will have e^{ax} and e^{bx} as independent solutions if and only if its characteristic equation is (r- a)(r- b)= 0.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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