Differentiate time derivative w/ respect to generalized var.

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SUMMARY

This discussion focuses on differentiating the velocity vector in cylindrical coordinates with respect to the generalized variables θ and r. The user seeks to understand the steps involved in calculating ∂v/∂θ and ∂v/∂r, emphasizing the importance of directional unit vectors eθ and eρ. A mistake was identified in the initial attempt, where the derivatives were incorrectly taken with respect to the time derivatives of θ and r instead of the variables themselves. The correct expressions for the cylindrical unit vectors in terms of Cartesian coordinates are provided for clarity.

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buildingblocs
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Homework Statement


Solve ∂v/∂θ and ∂v/∂r. (refer to attached image for equations)

Homework Equations


Refer to attached image. note that the velocity is expressed in cylindrical coordinates and attention must be paid to the directional unit vectors eθ and eρ.[/B]

The Attempt at a Solution


Have solution (refer to attached image). However would like to understand the general steps involved such to apply them to other equations with generalised variables and time derivatives.

If any additional information is required to solve please do not hesitate to ask.
 

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It looks like you took ##\frac{\partial v}{\partial \dot\theta}## and ##\frac{\partial v}{\partial \dot r}##, not ##\frac{\partial v}{\partial \theta}## and ##\frac{\partial v}{\partial r}##.

Can you express ##\hat e_\rho## and ##\hat e_\theta## in terms of ##\hat x## and ##\hat y##?
 
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1)Yes you are correct, I made that mistake.

2)Here are the cylindrical unit vectors expressed in Cartesian unit vectors.

converting_cylindrical_to_cartesian.png


C=Asinθ+Bcosθ
D=Acosθ-Bsinθ

Unit vectors, therefore A=B=1;

C=sinθ+cosθ
D=cosθ-sinθ
 

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