Differentiating a trig function to the power of 2

chung963
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Homework Statement


I'm doing a optimisation question and I get to a point where I have to verify a maximum using a double derivative and I need to differentiate -5sin^2(x)

Homework Equations


-5sin^2(x)


The Attempt at a Solution


-10cos(x)sin(x) I am not sure if the answer is positive or negative.
 
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-10cos(x)sin(x) would be your first derivative .
 
You are using the chain rule: -5sin^2(x) can be written as -5u^2 with u= sin(x). The derivative of -5u^2, with respect to u, is -10u and the derivative of u= sin(x) with respect to x is cos(x). Multiply those together.
 
it is negative and in order to find maximum value you have to differentiate once more
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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